回复 痛过的人 的帖子
There are total 29 units of biscuits;
Small boxes contain 18 units;
Big boxes contain 11 units (29-18);
Each small box contains ->18/14 = 9/7 units
Each big box contains ->11/7 units
10 pcs of biscuits ->11/7 units – 9/7 units=2/7units
1 unit-> 10*7/2=35 pcs
each small box contains->35*18/14 = 45 pcs
Answer: There were 45 pieces of biscuits in each small box.
回复 痛过的人 的帖子
不好意思，该一点。
There are total 29 units of biscuits（18/29 of the biscuits baked were packed in small boxes）;
Small boxes contain 18 units;
Big boxes contain 11 units (29-18);
Each small box contains ->18/14 = 9/7 units
Each big box contains ->11/7 units
10 pcs of biscuits ->11/7 units – 9/7 units=2/7 units
1 unit-> 10*7/2=35 pcs
Each small box contains->35*9/7 = 45 pcs
Answer: There were 45 pieces of biscuits in each small box
回复 痛过的人 的帖子
这种类型的问题用“置换”法好理解一些
TOTAL BISCUITS：29u
14small boxes—18u
7 big boxes—11u=7 small boxes+70biscuits
21 small boxes=27u
2u—70biscuits
18u–630biscuits
each small box has 45 biscuits.
谢谢各位帮忙 理解 万分感激
简化一下题目，总数（A）、14小盒子个和7个大盒子 大家都除以7就等同于新总数（B）、2个小盒子和一个大盒子，
B的18/29装在小盒子里面,也就是意味着B的9/29装在一个小盒子里面，剩下一个大盒子装B的11/29,，
大盒子比小盒子多装B的2/29。所以B的2/29=10，B的1/29=5,
小盒子装B的9/29=5×9=45
好多小六的数学问题还满难的.
太厉害啦