Georgette and her friends were assigned to fold papper stars in three weeks’ time.
In the first 11 days ,they folded 70 papper stars on each day.In the next 6 days ,
they fold 20% less than the total that they had folded in the last 11 days.
If they still had 108 papper stars to fold per day for the remaining number of days,
how many papper stars were they assigned to fold altogether in three weeks’ time?
我们解题: 11天6天4
70+432=502
502/20%=2510（最后11天包括中间6天在内）
2510-432-70=2008
770+2008+432=3210
也知道肯定错了，没法分析出来
看到数学题我就头疼，转身走了。
我也是，现在没法呀。
答案是1818。616+770+432=1818
你的做法对，计算错。
In the next 6 days ,
they fold 20% less than the total that they had folded in the last 11 days.
所以我们理解为：最后四天（108*4）+第11天（70）去除以20%
谢谢解题！！！