名校试卷上的
Jewel bought some strawberries and wanted to put them into boxes. If she put 4 strawberries into each box, there would be 3 strawberries left. If she put 6 strawberries into each box, she would have 5 strawberries left.
a) if the number of strawberries was between 100 and 150, how many strawberries did Jewel buy?
b) Jewel decided to put all the strawberries equally into bags of 16. Find the minimum number of bags that she would need.
a) 的答案是131， 可我觉得119也符合条件。 是我做错了吗？还是这题真的有两个解？
我觉得你对，两个解。
a） 有四个答案：107；119；131；143
等皮皮睡觉起来，我再让他来做一做。
这题的确四个答案：107，119，131，143。越来越发现，新加坡小学数学出题极不严谨。就连我儿子做奥数题，都经常指出书上出题条件上的漏洞。无奈！
楼上朋友们都好细心啊，我求出俩解后就没再算了。
遇到这样的题目真让人头痛啊
先确定a，b的范围：
100
还有一种解法：需要一点技巧。
4个4个数余3意味着再多一个的话就被4整除
6个6个数余5意味着再多一个的话就被6整除
题目就简化了，就是求解4和6的公倍减去1，也就是12的倍数落在100到150之间的减去1
108－1＝107。107+12＝119。119+12＝131。131+12＝143
回复 风寒 的帖子
两次的余数刚好都是比除数小1才可以这样做。如果是任意的呢？有没有简便的方法呢？
回复 yyhclt001212 的帖子
对不起，刚看到7楼的回复了。
P5 数学题目，有人会解答？
liming and wanghui had the same amount of money at first. After shopping, Abigail had 15 times as much money as Peiying. If Abigail spent $277 and Peiying spent $627, what was the total amount of money they had at first.
题目的名字是不是搞错啦，如果是算Abigail和Peiying的，我的算法如下：
627-277=350
15-1=14
350/14=25
627+25=652
652X2=1304
解法如图：